VCEENGINE ORACLE 1Z1-071 DESKTOP PRACTICE EXAM

VCEEngine Oracle 1z1-071 Desktop Practice Exam

VCEEngine Oracle 1z1-071 Desktop Practice Exam

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Oracle 1z1-071 certification exam covers a broad range of topics related to SQL programming language, such as data definition language (DDL), data manipulation language (DML), and data control language (DCL). In addition, the exam also covers various topics related to SQL functions, such as single-row functions, group functions, and conversion functions. 1z1-071 Exam also assesses the candidate's knowledge of schema objects, such as tables, views, indexes, and sequences.

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Earning the Oracle 1z1-071 Certification can open up a variety of career opportunities in the field of database management. Oracle SQL is widely used in various industries, including finance, healthcare, and technology. With this certification, individuals can demonstrate their proficiency in working with Oracle databases and SQL programming, making them more competitive in the job market.

Oracle Database SQL Sample Questions (Q294-Q299):

NEW QUESTION # 294
You need to produce a report where each customer's credit limit has been incremented by $1000. In the output, the customer's last name should have the heading Nameand the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?
SELECT cust_last_name AS "Name", cust_credit_limit + 1000

  • A. AS New Credit Limit
    FROM customers;
    SELECT cust_last_name AS Name, cust_credit_limit + 1000
  • B. AS "New Credit Limit"
    FROM customers;
    SELECT cust_last_name AS Name, cust_credit_limit + 1000
  • C. INITCAP ("NEW CREDIT LIMIT")
    FROM customers;
  • D. "New Credit Limit"
    FROM customers;
    SELECT INITCAP (cust_last_name) "Name", cust_credit_limit + 1000

Answer: B


NEW QUESTION # 295
Which two statements are true about the data dictionary?

  • A. Views with the prefix all_, dba_ and useb_ are not all available for every type of metadata.
  • B. Views with the prefix all_ display metadata for objects to which the current user has access.
  • C. The data dictionary does not store metadata in tables.
  • D. Views with the prefix dba_ display only metadata for objects in the SYS schema.
  • E. The data dictionary is accessible when the database is closed.

Answer: A,B

Explanation:
The data dictionary contains metadata (data about data) about the database and its objects.
A). False. DBA_ views display metadata for objects accessible to the database administrator, not only for the SYS schema.
B). True. ALL_ views display information about all the objects that the current user has access to. This does not necessarily mean the user has privileges on these objects, only that the user can see them.
C). False. The data dictionary is not accessible when the database is closed because it requires the database to be open in order to access the system tables.
D). True. Not all types of metadata are available in all three prefixes (ALL_, DBA_, USER_). Some specific metadata might only be available in one or two of these view types.
E). False. The data dictionary stores metadata in tables. The various views (ALL_, DBA_, USER_, etc.) provide different perspectives on this data.
References:
* Oracle Documentation on Data Dictionary and Dynamic Performance Views:
https://docs.oracle.com/cd/B28359_01/server.111/b28310/datadict.htm


NEW QUESTION # 296
View the Exhibit and examine the structure of the CUSTOMERS table.

Using the CUSTOMERS table, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?

  • A. SELECT NVL(TO_CHAR(cust_credit_limit*.15), 'Not Available') "NEW CREDIT" FROM customers;
  • B. SELECT NVL(cust_credit_limit, 'Not Available')*.15 "NEW CREDIT" FROM customers;
  • C. SELECT TO_CHAR(NVL(cust_credit_limit*.15, 'Not Available')) "NEW CREDIT" FROM customers;
  • D. SELECT NVL(cust_credit_limit*.15, 'Not Available') "NEW CREDIT" FROM customers;

Answer: D


NEW QUESTION # 297
SELECT *
FROM bricks,colors;
Which two statements are true?

  • A. You can add a USING clause with a join condition.
  • B. You can add a WHERE clause with filtering criteria.
  • C. It returns the number of rows in BRICKS plus the number of rows in COLORS.
  • D. It returnsthe same rows as SELECT * FROM bricks CROSS JOIN colors.
  • E. You can add an ON clause with a join condition.

Answer: B,D


NEW QUESTION # 298
Examine this partial query:
SELECT ch.channel_type, t.month, co.country_code, SUM(s.amount_sold) SALES FROM sales s, times t, channels ch, countries co WHERE s.time_ id = t.time id AND s.country_ id = co. country id AND s. channel id = ch.channel id AND ch.channel type IN (&apos;Direct Sales&apos;, &apos;Internet&apos;) AND t.month IN (&apos;2000-09&apos;, &apos;2000-10&apos;) AND co.country code IN (&apos;GB&apos;, &apos;US&apos;) Examine this output:

Which GROUP BY clause must be added so the query returns the results shown?

  • A. GROUP BY ch.channel_type, t.month, co.country code;
  • B. GROUP BY CUBE (ch. channel_ type, t .month, co. country code);
  • C. GROUP BYch. channel_ type, t.month,ROLIUP (co. country_ code) ;
  • D. GROUP BY ch.channel_type,ROLLUP (t month, co. country_ code) ;

Answer: A

Explanation:
A: True. The GROUP BY clause needs to include all non-aggregated columns from the SELECT list to provide the correct grouping for the output. The output shown in the image indicates that the data is grouped by channel_type, month, and country_code.
B: C, and D are incorrect because:
* B includes a ROLLUP which would introduce subtotals that are not reflected in the output shown.
* C specifies a CUBE, which would produce all possible combinations of groupings including the grand total, which is not shown in the output.
* D specifies a ROLLUP on country_code only, which would not correctly group by channel_type and month.


NEW QUESTION # 299
......

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